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Author Topic: RG and Diff  (Read 621 times)

Storm269

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RG and Diff
« on: September 04, 2009, 02:21:09 AM »
Hi everybody....out of curiosity would like to ask...is there any unit measure for the RG and diff ?
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charlest

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Re: RG and Diff
« Reply #1 on: September 04, 2009, 11:23:00 AM »
The unit of measurement for RG and RG differential is inches.
RG varies from 2.43" to 2.80".
RG differential varies from approximately .012" to the current legal maximum of .060". It used to be .080".

Is that what you mean?

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Storm269

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Re: RG and Diff
« Reply #2 on: September 05, 2009, 10:05:56 AM »
Hi Charlest
Yes that right...do you have any article on how this numbers come about ? Any info how to measure it on the ball ?
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Juggernaut

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Re: RG and Diff
« Reply #3 on: September 05, 2009, 11:44:37 AM »
Not charlest, but maybe I can help.  First, I'm pretty sure that they just recently voted to change the low RG minimum number from 2.43 up to 2.46 ARTICLE

  Now, as to how to measure it on a ball. It sounds complicated, but really isn't. Every bowling ball has an RG. RG is the abbreviation of the term "Radius of Gyration", an account or measurement of the distribution of the mass in an object from the geometric center.

  Every ball has two limits, which are called LOW RG and HIGH RG.  These states are easily found, because the pin marks the top of the weightblock, and that placement help determine which state the ball will roll in, depending on whether you have the pin closer to your axis point or closer to your track.

  As an example, I will use an imaginary ball as the subject.  We will say that this imaginary ball has an intermediate RG rating of 2.65 and a differential of 0.30. To find the HIGH and LOW RG numbers for this ball, you divide the differential number (0.30) by 2 (0.30/2) to get a value of 0.15, then both add AND subtract that value from the intermediate differential number (2.65+0.15=2.80 and 2.65-0.15=2.50).  Now, we see we have a ball whose HIGH RG rating is 2.80 and whose LOW RG rating is 2.50.

  What all this means is, if you drill the ball with the pin IN YOUR TRACK, you will have a ball with a 2.80 RG and if you drill the ball with the pin ON YOUR PAP, you will have a ball with a 2.50 RG.

  Now, you can measure the distance from your track to your pap, then divide that by 30 ( because the total differential is 0.30, or 30 "units"), to be able to tell just how far moving the pin either direction will alter the RG by 0.01. ( As an example, if the distance from your track to your pap was 6 inches, you would divide 6 by 30, getting the value 0.2, or 1/5 of an inch.  Thusly, for every 1/5 of an inch that you move your pin either towards or away from your pap, you would alter the ending RG by a factor of 0.01 )





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